Um analista de teste aplica cobertura de escolha base a um sistema com 4 parâmetros, cada um com 3 valores. O TA seleciona uma combinação base. Quantos casos de teste são necessários no mínimo?
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Correct answer: 9 (a combinação base + 2 valores não-base por parâmetro × 4 parâmetros = 1 + 8 = 9)
Reference: https://istqb.org/wp-content/uploads/sdm-uploads/ISTQB-CTAL-TA-Syllabus-v4.0-EN-4.pdf
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02 — The Myelin Layer · Canonical Discussion
Where the exam tries to trick you — and how those who passed solved it.
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Official Answer (B): 9 (a combinação base + 2 valores não-base por parâmetro × 4 parâmetros = 1 + 8 = 9)
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